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9x^2-6x=157
We move all terms to the left:
9x^2-6x-(157)=0
a = 9; b = -6; c = -157;
Δ = b2-4ac
Δ = -62-4·9·(-157)
Δ = 5688
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5688}=\sqrt{36*158}=\sqrt{36}*\sqrt{158}=6\sqrt{158}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6\sqrt{158}}{2*9}=\frac{6-6\sqrt{158}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6\sqrt{158}}{2*9}=\frac{6+6\sqrt{158}}{18} $
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